Hallo Leute,
dies ist mein erster Beitrag hier und entdecke seid ein paar Tagen die Welt der Mikrocontroller.
Folgenden Sketch habe ich auf meinem UNO-R3 an laufen.
jetzt verzweifel ich an der Fragestellung die Werte zu nutzen. Hierfür wollte ich eine LED an Pin 3 auf HIGH setzen wenn der Messwert unter 15cm fällt.Code:int pingPin = 13; int inPin = 12; void setup() { Serial.begin(9600); } void loop() { // establish variables for duration of the ping, // and the distance result in inches and centimeters: long duration, inches, cm; // The PING))) is triggered by a HIGH pulse of 2 or more microseconds. // Give a short LOW pulse beforehand to ensure a clean HIGH pulse: pinMode(pingPin, OUTPUT); digitalWrite(pingPin, LOW); delayMicroseconds(2); digitalWrite(pingPin, HIGH); delayMicroseconds(10); digitalWrite(pingPin, LOW); // The same pin is used to read the signal from the PING))): a HIGH // pulse whose duration is the time (in microseconds) from the sending // of the ping to the reception of its echo off of an object. pinMode(inPin, INPUT); duration = pulseIn(inPin, HIGH); // convert the time into a distance inches = microsecondsToInches(duration); cm = microsecondsToCentimeters(duration); Serial.println(cm, DEC); delay(100); } long microsecondsToInches(long microseconds) { // According to Parallax's datasheet for the PING))), there are // 73.746 microseconds per inch (i.e. sound travels at 1130 feet per // second). This gives the distance travelled by the ping, outbound // and return, so we divide by 2 to get the distance of the obstacle. return microseconds / 74 / 2; } long microsecondsToCentimeters(long microseconds) { // The speed of sound is 340 m/s or 29 microseconds per centimeter. // The ping travels out and back, so to find the distance of the // object we take half of the distance travelled. return microseconds / 29 / 2; }
Folgender Code fiel mir dazu ein.
Diesen Code habe ich am Ende angefügt.Code:if (digitalRead(inPin)<=435){ // 15cm * 29 microseconds per centimeter (sollte die Distanz beschreiben) digitalWrite(3, HIGH); } else { digitalWrite(3, LOW); }
Kann mir jemand Helfen mein Problem zu lösen?Code:int pingPin = 13; int inPin = 12; void setup() { Serial.begin(9600); pinMode(3, OUTPUT); } void loop() { // establish variables for duration of the ping, // and the distance result in inches and centimeters: long duration, inches, cm; // The PING))) is triggered by a HIGH pulse of 2 or more microseconds. // Give a short LOW pulse beforehand to ensure a clean HIGH pulse: pinMode(pingPin, OUTPUT); digitalWrite(pingPin, LOW); delayMicroseconds(2); digitalWrite(pingPin, HIGH); delayMicroseconds(10); digitalWrite(pingPin, LOW); // The same pin is used to read the signal from the PING))): a HIGH // pulse whose duration is the time (in microseconds) from the sending // of the ping to the reception of its echo off of an object. pinMode(inPin, INPUT); duration = pulseIn(inPin, HIGH); // convert the time into a distance inches = microsecondsToInches(duration); cm = microsecondsToCentimeters(duration); Serial.println(cm, DEC); delay(100); } long microsecondsToInches(long microseconds) { // According to Parallax's datasheet for the PING))), there are // 73.746 microseconds per inch (i.e. sound travels at 1130 feet per // second). This gives the distance travelled by the ping, outbound // and return, so we divide by 2 to get the distance of the obstacle. return microseconds / 74 / 2; } long microsecondsToCentimeters(long microseconds) { // The speed of sound is 340 m/s or 29 microseconds per centimeter. // The ping travels out and back, so to find the distance of the // object we take half of the distance travelled. return microseconds / 29 / 2; if (digitalRead(inPin)<=435){ // 15cm * 29ms/cm digitalWrite(3, HIGH); } else { digitalWrite(3, LOW); } }
Dank in Voraus.![]()







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