HalloZitat von Anonymous
Irgendwie erscheint es logisch das das nicht funzt wenn man einen Blick in das Datenblatt wirft:
The output voltage of the differential or gauge sensor
increases with increasing pressure applied to the pressure
side (P1) relative to the vacuum side (P2). Similarly, output
voltage increases as increasing vacuum is applied to the
vacuum side (P2) relative to the pressure side (P1).
Fällt Dir was auf ?
LG
Rubi
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